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In rhombus MPKN with an obtuse angle K the diagonals intersect each other at point E. The measure of one of the angles of a ∆PK...Asked by Anonymous
In rhombus MPKN with an obtuse angle K the diagonals intersect each other at point E. The measure of one of the angles of a ∆PKE is equal 16°. Find the measures of all angles of ∆PKE and ΔPMN.
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Answered by
Steve
it can only be angle PKE=16° That means angle PKN=32° and KPM=148°
MK and PN bisect the angles of the rhombus. Now you can get all the angles you need. Note that diagonals are perpendicular.
MK and PN bisect the angles of the rhombus. Now you can get all the angles you need. Note that diagonals are perpendicular.
Answered by
Karla
m∠KEP = 90°
m∠EKP = 74°
m∠EPK = 16°
m∠N PM= 16°
m∠MNP = 16
m∠M = 148°
m∠EKP = 74°
m∠EPK = 16°
m∠N PM= 16°
m∠MNP = 16
m∠M = 148°
Answered by
SmartNerd
well Karla, your answer is right, you should show work so ppl will be able to understand
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