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This is a rt. triangle:
A = 0.5b*h = 0.5*6*8 = 24 Ft^2.
A = 0.5b*h = 0.5*6*8 = 24 Ft^2.
Area = sqrt(s * (s - a) * (s - b) * (s - c))
where s is the semi-perimeter of the triangle, which is calculated as:
s = (a + b + c) / 2
In your case, the side lengths of the triangular lot are given as 10ft, 8ft, and 6ft. So, we can substitute these values into the formulas.
Calculating the semi-perimeter:
s = (10ft + 8ft + 6ft) / 2
s = 24ft / 2
s = 12ft
Calculating the area:
Area = sqrt(12ft * (12ft - 10ft) * (12ft - 8ft) * (12ft - 6ft))
Area = sqrt(12ft * 2ft * 4ft * 6ft)
Area = sqrt(576ft^2)
Area = 24ft^2
Therefore, the area of the lot that would be needed to cover by soil is 24 square feet.