Question

b. Explain why the initial value problem y'=4xsqrt(1-y^2) with y(0) = 4 does not have a solution.

I already solved the differential equation and got y=sin(2x^2+C)

I don't know what to do from there

Answer 1

what you do is use the rest of the information they gave you: y(0)=4

So, you have to find C using

4 = sin(2*0+C)

Now, when does sin(θ) = 4? Never!