Asked by alex
At a nuclear power plant, water at 6degress Celius from a nearby lake is used in a heat exchange to condense spent steam at a temperature of 115 degees C to water at 80 degrees C. If the cooling water returns to the lake at a temperature of 18 degrees C, what mass of lake water is needed per kilogram of steam?
My solution:
Q lost = - q gained
m x 4200 x (18-6) = - 1kg x 4280 x (80-115)
m= 147000/50400
m= 2.9kg
The right answer is 48kg. Thank you for your help
My solution:
Q lost = - q gained
m x 4200 x (18-6) = - 1kg x 4280 x (80-115)
m= 147000/50400
m= 2.9kg
The right answer is 48kg. Thank you for your help
Answers
Answered by
Scott
cool steam to 100ºC
condense steam to water
cool water to 80ºC
two specific heats (water and steam)
... one heat of vaporization
condense steam to water
cool water to 80ºC
two specific heats (water and steam)
... one heat of vaporization
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