Asked by Regina
Assuming that Switzerland's population is growing exponentially at a continuous rate of 0.21 percent a year and that the 1988 population was 6.8 million, write an expression for the population as a function of time in years. (Let t=0t=0 in 1988.)
I got 6.8 e^[0.021(t - 1988)] but it says it's wrong. I don't know what I'm doing wrong.
I got 6.8 e^[0.021(t - 1988)] but it says it's wrong. I don't know what I'm doing wrong.
Answers
Answered by
Steve
It is wrong. Your equation uses a rate of 2.1%. a .21% growth rate means
6.8 * 1.0021^(t-1988)
You can use a base of e, but that would be
ln 1.21 = 0.0021
6.8 e^(0.0021(t-1988))
or, if t is defined as the number of years since 1988,
6.8*1.0021^t
or
6.8 e^(0.0021t)
6.8 * 1.0021^(t-1988)
You can use a base of e, but that would be
ln 1.21 = 0.0021
6.8 e^(0.0021(t-1988))
or, if t is defined as the number of years since 1988,
6.8*1.0021^t
or
6.8 e^(0.0021t)
Answered by
Regina
That answer is wrong.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.