Asked by Jae M.
An abandoned building's value is 230(0.95)^t thousand dollars. When will Etienne be able to buy the building with his savings account, which has $150,000 at year t= 0 and is growing by 11% per year?
Answers
Answered by
Jae M.
I just need help setting up the formula, that's all :)
Answered by
Reiny
If I read it correctly you want
230000(.95)^t = 150000(1.11)^t
23(.95^t) = 15(1.11)^t
take logs of both sides and use log rules
log 23 + t log .95 = log 15 + t log 1.11
log 23 - log 15 = t(log 1.11 - log .95)
carry on
230000(.95)^t = 150000(1.11)^t
23(.95^t) = 15(1.11)^t
take logs of both sides and use log rules
log 23 + t log .95 = log 15 + t log 1.11
log 23 - log 15 = t(log 1.11 - log .95)
carry on
Answered by
Jae M.
thank you very much! I understand it now :)
Answered by
Steve
or, you can get all the exponents over a single value:
23(.95^t) = 15(1.11)^t
(.95^t)/(1.11)^t = 15/23
(.95/1.11)^t = 15/23
t log(0.856) = log(0.652)
t = log(0.652)/log(0.856) = 2.751
You can see that Reiny's value will agree, since subtracting logs lets you divide numbers. His will probably be more accurate, since the final rounding error will be deferred until the last step.
23(.95^t) = 15(1.11)^t
(.95^t)/(1.11)^t = 15/23
(.95/1.11)^t = 15/23
t log(0.856) = log(0.652)
t = log(0.652)/log(0.856) = 2.751
You can see that Reiny's value will agree, since subtracting logs lets you divide numbers. His will probably be more accurate, since the final rounding error will be deferred until the last step.
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