Asked by alex
                An air-track cart with mass m1=0.29kg and initial speed v0=0.95m/s collides with and sticks to a second cart that is at rest initially.
Part A
If the mass of the second cart is m2=0.55kg, how much kinetic energy is lost as a result of the collision?
            
            
        Part A
If the mass of the second cart is m2=0.55kg, how much kinetic energy is lost as a result of the collision?
Answers
                    Answered by
            Ms. Sue
            
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                    Answered by
            alex
            
    An air-track cart with mass m1=0.29kg and initial speed v0=0.95m/s collides with and sticks to a second cart that is at rest initially. 
Part A
If the mass of the second cart is m2=0.55kg, how much kinetic energy is lost as a result of the collision?
    
Part A
If the mass of the second cart is m2=0.55kg, how much kinetic energy is lost as a result of the collision?
                    Answered by
            Wasif
            
    Initial KE = 0.5*0.29*0.95^2
= 0.1308625
Final KE= (0.5*0.29*0.95^2)-(0.5*(0.29+0.55)*((0.29*0.95)/(0.29+0.55))^2)
= 0.0451787
lost in the collision= Final KE - Initial KE
= 0.0451787-0.1308625
= -0.08568 J -------> Answer
    
= 0.1308625
Final KE= (0.5*0.29*0.95^2)-(0.5*(0.29+0.55)*((0.29*0.95)/(0.29+0.55))^2)
= 0.0451787
lost in the collision= Final KE - Initial KE
= 0.0451787-0.1308625
= -0.08568 J -------> Answer
                    Answered by
            matt
            
    Still need answer, above one is wrong
    
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