Question

To make a bounce pass, a player throws a 0.60-kg basketball toward the floor. The ball hits the floor with a speed of 5.2 m/s at an angle of 60 ∘ to the vertical.
Part A
If the ball rebounds with the same speed and angle, what was the magnitude of the impulse delivered to it by the floor?

Answer 1

impulse = change of momentum
all vertical, no change in horizontal
speed from -v cos 60 to + v cos 60

2 m v cos 60