Asked by gasana
3. A solution is made by dissolving 5.00 g of impure sodium hydroxide in water and making it up to 1.00dm3 of solution. 25.0 cm3 of this solution is neutralized by 30.0 cm3 of hydrochloric acid of concentration 0.102 mol/dm3.
a) Calculate the number of mole of HCl.
b) Calculate the number of sodium hydroxide.
c) Calculate the percentage purity of the sodium hydroxide
a) Calculate the number of mole of HCl.
b) Calculate the number of sodium hydroxide.
c) Calculate the percentage purity of the sodium hydroxide
Answers
Answered by
DrBob222
NaOH + HCl ==> NaCl + H2O
mols HCl = M x L = ?
mols NaOH = mols HCl (from the 1:1 coefficients in the balanced equation)
grams NaOH = mols NaoH x molar mass NaOH
% NaOH = (g NaOH/g sample)*100 = >
mols HCl = M x L = ?
mols NaOH = mols HCl (from the 1:1 coefficients in the balanced equation)
grams NaOH = mols NaoH x molar mass NaOH
% NaOH = (g NaOH/g sample)*100 = >
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