Asked by Jae M.
Write the overall cell reaction for a cell containing aluminum metal and Zinc(II)sulfate
so would it be:
Al (s) + ZnSO4 (aq) <---> Al3+ + ZnSO4 ??????
I tried to do it myself but I'm a bit confused...
I'm confused about the charges because isn't ZnSO4 neutral since Zn is 2+ and SO4 is -2, so how would the charge change?
so would it be:
Al (s) + ZnSO4 (aq) <---> Al3+ + ZnSO4 ??????
I tried to do it myself but I'm a bit confused...
I'm confused about the charges because isn't ZnSO4 neutral since Zn is 2+ and SO4 is -2, so how would the charge change?
Answers
Answered by
DrBob222
Al goes into solution; Zn comes out.
2Al + 3ZnSO4 ==> Al2(SO4)3 + 3Zn(s)
Atoms balance.
Charges balance.
6 electrons lost (2Al ==>2Al^3+ + 6 e) and 6 electrons gained (3Zn^2+ + 6e ==> 2Zn).
2Al + 3ZnSO4 ==> Al2(SO4)3 + 3Zn(s)
Atoms balance.
Charges balance.
6 electrons lost (2Al ==>2Al^3+ + 6 e) and 6 electrons gained (3Zn^2+ + 6e ==> 2Zn).
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