Asked by Amanda
An Atwood's machine is built from m1=1kg and m2=2kg. The mass less string is passed over a friction less, mass less pulley. When the system is released from rest, what is the tension in the string?
Answers
Answered by
bobpursley
force down:2*9.8
force up: 1*9.8
Net force= forcedown-forceup=ma
solve for a: mass=3kg
(9.8)(2-1)=3*a
a= 9.8/3
tension= mass*g-+mass*acceleration
tensionheavy side= 2(g-g/3)=4g/3
tensionlight side=1g+1g/3=4g/3
force up: 1*9.8
Net force= forcedown-forceup=ma
solve for a: mass=3kg
(9.8)(2-1)=3*a
a= 9.8/3
tension= mass*g-+mass*acceleration
tensionheavy side= 2(g-g/3)=4g/3
tensionlight side=1g+1g/3=4g/3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.