Question

a mass is suspended on a vertical spring oscillates with a period of 0.5 sec .When the mass is attached to the spring and allowed to hang at rest .By how much is the spring stretched?


































wouldn't that depend on the spring?

2PI/period=sqrt(k/m)

k/m= (2PI/5)^2

force=kx
x=force/k= mg/k= 9.8*(5/2PI)^2
check that.

Related Questions

0.460 kg mass suspended from a spring oscillates with a period of 1.50 s. How much mass must be add... A 0.500kg mass suspended from a spring oscillates with a period if 1.50s. How much mass must be adde...