Asked by shaheen
a mass is suspended on a vertical spring oscillates with a period of 0.5 sec .When the mass is attached to the spring and allowed to hang at rest .By how much is the spring stretched?
Answers
Answered by
bobpursley
wouldn't that depend on the spring?
2PI/period=sqrt(k/m)
k/m= (2PI/5)^2
force=kx
x=force/k= mg/k= 9.8*(5/2PI)^2
check that.
2PI/period=sqrt(k/m)
k/m= (2PI/5)^2
force=kx
x=force/k= mg/k= 9.8*(5/2PI)^2
check that.
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