Asked by Rachel
Please help me proof the identity. This isn't even math to me, I can not understand it so please show all work. God bless
A)1-cos2x/sin2x=tanx
B) sin4x/sinx=4cosxcos2x
A)1-cos2x/sin2x=tanx
B) sin4x/sinx=4cosxcos2x
Answers
Answered by
Steve
If this isn't even math to you, you clearly haven't been paying attention during the discussion of the double-angle formulas ...
(1-cos2x)/sin2x
= (1-(2cos^2x-1))/(2sinx cosx)
= (2-2cos^2x)/(2sinx cosx)
= 2sin^2x/(2sinx cosx)
= sinx/cosx
= tanx
sin4x/sinx
= (2sin2x cos2x)/sinx
= (2*2sinx cosx cos2x)/sinx
= 4cosx cos2x
(1-cos2x)/sin2x
= (1-(2cos^2x-1))/(2sinx cosx)
= (2-2cos^2x)/(2sinx cosx)
= 2sin^2x/(2sinx cosx)
= sinx/cosx
= tanx
sin4x/sinx
= (2sin2x cos2x)/sinx
= (2*2sinx cosx cos2x)/sinx
= 4cosx cos2x
Answered by
Rachel
Sorry steve not everyone is as smart as you. Thanks for your help tho
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