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Asked by Austin

Find all the real zeros for the equation p(x)=x^3+4x^2+x-6
8 years ago

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Answered by Scott
inspection shows 1 as a root (zero)

so (x - 1) is a factor

dividing p(x) by (x - 1) will leave a quadratic that can be broken down
8 years ago
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Find all the real zeros for the equation p(x)=x^3+4x^2+x-6

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