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Asked by Brian

the thirteenth term of an arythmeticprogression is 27. given that the seventh term equals to three times the second term, find:
the first term nd the common difference of the progression
8 years ago

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Answered by Steve
a+12d = 27
a+6d = 3(a+d)

Now just solve for a and d.
8 years ago
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the thirteenth term of an arythmeticprogression is 27. given that the seventh term equals to three times the second term, find:
the first term nd the common difference of the progression

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