Asked by Brian
the thirteenth term of an arythmeticprogression is 27. given that the seventh term equals to three times the second term, find:
the first term nd the common difference of the progression
the first term nd the common difference of the progression
Answers
Answered by
Steve
a+12d = 27
a+6d = 3(a+d)
Now just solve for a and d.
a+6d = 3(a+d)
Now just solve for a and d.
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