Question
Three students came to the bake sale to shop. The sum of their ages is 33. The product of their ages is 1,320. How old are they?
Answers
Damon
well 11^3 = 1331
and 3*11 = 33
one of the ages must end in 0 or 5 to get 1320 as a product
so try 10*11*12 = 1320 Well now, how do you like that ? :)
and 3*11 = 33
one of the ages must end in 0 or 5 to get 1320 as a product
so try 10*11*12 = 1320 Well now, how do you like that ? :)
Reiny
10,11, and 12
I figured that they were probably close in ages, so (age)^3 is approximately 1320
took the cuberoot of 1320 which was close to 11
sure enough 1320 divides by 11 120 time
and 120 = 10x12
and sure enough 10+11+12 = 33
I figured that they were probably close in ages, so (age)^3 is approximately 1320
took the cuberoot of 1320 which was close to 11
sure enough 1320 divides by 11 120 time
and 120 = 10x12
and sure enough 10+11+12 = 33
Reiny
ain't it scary how we think alike?
LOL
LOL
Damon
That is pretty funny :)
Junior Ortega
The answer is that there ages are 10,11,12