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Asked by Sandy East Ward

How would I rewrite this in polar form? // x^2 + y^2 - 6y - 8 = 0
8 years ago

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Answered by Steve
x^2+y^2-6y-8 = 0
r^2 - 6rsinθ - 8 = 0
8 years ago
Answered by Anonymous
r^2 = 6r sin theta +8
4 years ago
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How would I rewrite this in polar form? // x^2 + y^2 - 6y - 8 = 0

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