Question

Sam invested $1900, part of it at 6% and the rest at 8% yearly interest. The yearly income on the 8% investment was $32 more than twice the income from the 6% investment. How much did he invest at each rate?


work so far:
x + y = 1900
.06x + .08y = ?

Thank you.

Answer 1

You have tried to use the model where they give you the total interest earned. This one does not do that. Instead, if you read what was written, your second equation must be

.08y = 32 + 2*.06x

Answer 2

So my two equations are...

x + y = 1900
.08y = 32 + .06x(2)

Yes?

Answer 3

yes

Answer 4

you invested a total of $30,000 at 3% and 41/2% simple interest . during one year the two accounts earned $1200. how much did you invest in each account