Question

A, B and C are 3 points on the level ground.B is due south of A . The baering of C from A is 085. A vertical mast of height 50m stands at A. The angle of elevation of T from B is 44 and the angle of elevation of T from C is 28 Calculate AB,AC, CB

50/AC = tan28°
50/AB = tan44°

Now use the law of cosines to find BC
Thanks Steve,
BUt How do you know its a right angled triangle so that you can apply tan
the vertical mast makes a right angle with the level ground, right?
Hi Steve
Actually the diagram given is already drawn in 2D!. I couldnt figure out that if I think in 3 D then T is above point A and will make a right angle with the lines AB and AC
Thanks so much for opening my eyes and helping me visualize the diagram from a different angle!! If the diagram wasnt given then I think i would have noticed.
You are right.The vertical mast has to be at right angle with the level ground!

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