Asked by charmen angcud
A 0.5-kg block slides along a horizontal frictionless surface at 2m/s. It is brought to rest by compressing a very long spring of spring constant 800N/m. The maximum spring compression is:
Answers
Answered by
Henry
Fb = M*g = 0.5 * 9.8 = 4.9 N. = Force of block.
d = 4.9N/800N * 1m = 0.006125 m. = 0.6125 cm.
d = 4.9N/800N * 1m = 0.006125 m. = 0.6125 cm.
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