Asked by Mycah
Verify whether the given equation (y=x^2+4x) is a solution to this given equation [(xdy/dx)=x^2+y]
Answers
Answered by
Reiny
y=x^2+4x
dy/dx = 2x + 4
checking in
(xdy/dx)=x^2+y
LS = x(2x+4)
= 2x^2 + 4x
RS = x^2 + x^2 + 4x
= 2x^2 + 4x
= LS
Yes, it is
dy/dx = 2x + 4
checking in
(xdy/dx)=x^2+y
LS = x(2x+4)
= 2x^2 + 4x
RS = x^2 + x^2 + 4x
= 2x^2 + 4x
= LS
Yes, it is
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