Asked by sinti
Pushing on the pump of a soap dispenser compresses a small spring. When the spring is compressed 0.55 cm , its potential energy is 0.0020 J
a.What is the force constant of the spring? i found the fist answer is 130N/M
B. What compression is required for the spring potential energy to equal 0.0079 J ? pls help part with b
a.What is the force constant of the spring? i found the fist answer is 130N/M
B. What compression is required for the spring potential energy to equal 0.0079 J ? pls help part with b
Answers
Answered by
bobpursley
PE=1/2 kx^2
.0020=1/2 k (.055^2)
solve for k
b. PE is directly proportional to the saqaure of compression, so
.0079/.0020 = (x/.55cm)^2
x in cm= .55cm * sqrt(.0079/.0020 )
.0020=1/2 k (.055^2)
solve for k
b. PE is directly proportional to the saqaure of compression, so
.0079/.0020 = (x/.55cm)^2
x in cm= .55cm * sqrt(.0079/.0020 )
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.