Question

The fixed cost of producing five units of a particular commodity is given as #900 while the total cost of producing the same five units of this commodity is #1000.the marginal cost of the 6th unit produced later is #200.calculate the average variable cost for the production of 6 unit of this commodity

Answer 1

∑(x-x̅)(y-y̅)

Answer 2

n∑xy - (∑x)(∑y)
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√(n∑x^2 - (∑x)^2) √(n∑y^2-(∑y)^2)

Answer 3

          n∑xy - (∑x)(∑y)
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√(n∑x^2 - (∑x)^2) √(n∑y^2-(∑y)^2)

Answer 4

              n∑xy - (∑x)(∑y)
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√(n∑x^2 - (∑x)^2) √(n∑y^2-(∑y)^2)

Answer 5

∑(x-x̅)(y-y̅)
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√(∑(x-x̅)^2) √(∑(y-y̅)^2)

Answer 6

        ∑(x-x̅)(y-y̅)
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√(∑(x-x̅)^2) √(∑(y-y̅)^2)

Answer 7

              n∑xy - (∑x)(∑y)         ∑(x-x̅)(y-y̅)

---------------------------------------------- = -------------------------------
√(n∑x^2 - (∑x)^2) √(n∑y^2-(∑y)^2) √(∑(x-x̅)^2) √(∑(y-y̅)^2)

Answer 8

              n∑xy - (∑x)(∑y)         ∑(x-x̅)(y-y̅)
---------------------------------------------- = -------------------------------
√(n∑x^2 - (∑x)^2) √(n∑y^2-(∑y)^2) √(∑(x-x̅)^2) √(∑(y-y̅)^2)

Answer 9

              n∑xy - (∑x)(∑y);       &nbsp        ∑(x-x̅)(y-y̅)
---------------------------------------------- = -------------------------------
√(n∑x^2 - (∑x)^2) √(n∑y^2-(∑y)^2);   &nbsp√(∑(x-x̅)^2) √(∑(y-y̅)^2)

Answer 10

              n∑xy - (∑x)(∑y);       &nbsp            ∑(x-x̅)(y-y̅)
---------------------------------------------- = -------------------------------
√(n∑x^2 - (∑x)^2) √(n∑y^2-(∑y)^2)    √(∑(x-x̅)^2) √(∑(y-y̅)^2)

Answer 11

              n∑xy - (∑x)(∑y)            &nbsp            ∑(x-x̅)(y-y̅)
---------------------------------------------- = -------------------------------
√(n∑x^2 - (∑x)^2) √(n∑y^2-(∑y)^2)    √(∑(x-x̅)^2) √(∑(y-y̅)^2)

Answer 12

              n∑xy - (∑x)(∑y)                &nbsp            ∑(x-x̅)(y-y̅)
---------------------------------------------- = -------------------------------
√(n∑x^2 - (∑x)^2) √(n∑y^2-(∑y)^2)    √(∑(x-x̅)^2) √(∑(y-y̅)^2)