Asked by Prateekshya

A person walks on the building.He slips 1m for every 5m he climbs. If the building is 53m high and he takes 5 seconds to climb 1m. Find the total time taken by him to get on the top of the building.
Answered by Steve
Since you don't say that each 5m portion is a separate attempt (like walking up stairs), I'll assume that his slippage is continuous as he climbs.

That is, it takes him 5*5=25 seconds to climb 5-1=4 meters.

So, his rate of ascent is 4/25 m/s

It will take him 53/(4/25) = 1325/4 = 331.25 seconds to make the climb.

If the climb has to be broken into discrete chunks of 5m each, then things change some.
Answered by Rajneesh vaishya
(n-1)×25/4=325sec
Where n=53
&4m in25 sec
Answered by Anonymous
Answer upper bale ka galat h
Answered by Sonal
5m=25seconds
5-1=4m(as he slips 1m for every5m)
Total height of building=53m
He will ned53/4=13sec(Remainder 1ignored)
25*3=325seconds
So, he needs 325sec to climb the building.
Answered by Ayusk kr sinha
Yes
Answered by Anonymous
5m 25sec.