Asked by Sandhya
A bicycle with wheels of 70.0 cm diameter is going at a speed of 12.0 m/s.How fast is a point on the rim at the top of one of the wheels moving relative to the ground?
Answers
Answered by
drwls
The angular velocity of the wheel is
w = V/R = 12.0/0.700 = 17.14 rad/s
Because the contact point of the wheel with the road is an "instant center" of rotation, a point at the top of the wheel moves at a velocity 2 w = 2 R * (V/R) = 2 V = 24 m/s.
w = V/R = 12.0/0.700 = 17.14 rad/s
Because the contact point of the wheel with the road is an "instant center" of rotation, a point at the top of the wheel moves at a velocity 2 w = 2 R * (V/R) = 2 V = 24 m/s.
Answered by
Sandhya
Thanks for your quick response
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.