Asked by Jason
Aluminum is produced by the electrolysis of aluminum oxide (Al2O3, bauxite ore) dissolved in molten cryolyte (Na2AlF6). Calculate the mass of aluminum that can be produced in one day in an electrolytic cell operating continuously at 1.0 x 105 amps. The cryolite does not react
Answers
Answered by
DrBob222
# coulombs = amps x seconds = 1E5 x (24 hr/day) x (60 min/hr) x (60 sec/min) = ?
96,485 coulombs will electrolyze approx 27/3 g Al (atomic mass Al/3) and I'll call that 9 g Al but you should look up the atomic mass Al and go from there.
So g Al = 9 g Al x (# coulombs/96,485) = ?
96,485 coulombs will electrolyze approx 27/3 g Al (atomic mass Al/3) and I'll call that 9 g Al but you should look up the atomic mass Al and go from there.
So g Al = 9 g Al x (# coulombs/96,485) = ?