Asked by Angel
Check my answer-
Solve the system of equations algebraically. Show all of your steps.
Y=x^2+2x
Y=3x+20
My answer:
X^2+2x+3x+20
X^2-x-20
(x-5),(x+4)=0
x=5, x=-4
y=35, y=8
Thank you!
Solve the system of equations algebraically. Show all of your steps.
Y=x^2+2x
Y=3x+20
My answer:
X^2+2x+3x+20
X^2-x-20
(x-5),(x+4)=0
x=5, x=-4
y=35, y=8
Thank you!
Answers
Answered by
Reiny
No, you might have come up mysteriously with the answer but it does not follow from what you did.
You start off with two lines are are not equations,
X^2+2x+3x+20
X^2-x-20 ----> this does not follow from the previous line,
then in the third line all of a sudden you have
.... = 0
proper way:
x^2 + 2x = 3x + 20 , since Y = Y
x^2 - x - 20 = 0
(x-5)(x+4) = 0
x = 5 or x =-4
if x = 5, y = 3(5) + 20 = 35
if x = -4, y = 3(-4) + 20 = 8
You start off with two lines are are not equations,
X^2+2x+3x+20
X^2-x-20 ----> this does not follow from the previous line,
then in the third line all of a sudden you have
.... = 0
proper way:
x^2 + 2x = 3x + 20 , since Y = Y
x^2 - x - 20 = 0
(x-5)(x+4) = 0
x = 5 or x =-4
if x = 5, y = 3(5) + 20 = 35
if x = -4, y = 3(-4) + 20 = 8
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