Asked by Anna
There were d passengers in the train. 15% of all of them went in the first car, 20% went in the second car. How many passengers were in the rest of the train?
D - 0.15d + (0.15d*0.2) + ?
0.15 + 0.03 = 0.18
I don't know what to do next?
D - 0.15d + (0.15d*0.2) + ?
0.15 + 0.03 = 0.18
I don't know what to do next?
Answers
Answered by
Ms. Sue
100 - 15 - 20 = 65% were in the rest of the train.
65% = 0.65d
65% = 0.65d
Answered by
Cheetos
The answer is 0.65d, and like if u go to RSM
Answered by
Jamie
I go to RSM its the worst but for the homework i just copy and paste like if u do the same
Answered by
o
RSM RSM RSM RSM RSM RSM
Answered by
wow
wow im gonna tell ms.donna
Answered by
....
This is an rsm problem and I can tell you for SURE that it isn't 0.65d bc I checked it plz help me
Answered by
...
its 0.65d. I got to RSM too and i got it correct
Answered by
Michael
it's 0.65d
15+20=35
100-35=65
15+20=35
100-35=65
Answered by
HEHE
it's .65d it worked on my hw.
Answered by
Anonymous
0.65d is right for rsm homwerk
Answered by
Someone
I do RSM too, final in couple of weeks
Answered by
JustCallMeYeet
If u will report this to RSM won't RSM ask u why u were on the webpage in the first place?
Answered by
Matt
YOU JUST HAVE DO ADD THE D AT THE END OR ELSE ITS WRONG
Answered by
Comfirmed RSM
0.65d CONFIRMED IM RSM
Answered by
RSM HATER
It’s 65d I hate RSM but my parents want me to go there
Answered by
Bot
I'm sorry to say this, but the correct answer is indeed 0.65d. You can solve it as follows:
Percentage of passengers in the first and second car = 15% + 20% = 35%
Therefore, percentage of passengers in the rest of the train = 100% - 35% = 65%
So, the number of passengers in the rest of the train can be represented as:
0.65d
I hope this clears up any confusion. Let me know if you have any other questions!
Percentage of passengers in the first and second car = 15% + 20% = 35%
Therefore, percentage of passengers in the rest of the train = 100% - 35% = 65%
So, the number of passengers in the rest of the train can be represented as:
0.65d
I hope this clears up any confusion. Let me know if you have any other questions!
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