Ask a New Question

Asked by Erin

A 1.00 mL aliquot of solution A was diluted to 50.00 mL using 0.02 M Fe(III), forming solution B (reaction 2)

By looking at this how many moles of sodium salicylate were in the 1.00 mL aliquot used to prepare solution B?
8 years ago

Answers

Answered by DrBob222
Nonsense. How do you know solution A had any sodium salicylate in it?
8 years ago
Answered by Lily
DrBob222, not helpful at all.
5 years ago

Related Questions

A 5.0ml aliquot of a sample was transferred to a 25.0ml flask and acidified by addition of 2.5ml of... A 100.0-mL aliquot of 0.100 M diprotic acid H2A (pK1 = 4.00, pK2 = 8.00) was titrated with 1.00 m Na... A 100.0 mL aliquot of 0.200 M aqueous potassium hydroxide is mixed with 100.0 mL of 0.200 mL of 0.20... A 100.0 mL aliquot of 0.100 M weak base B (pKb=5.00) was titrated with 1.00 M HClO4. Find the pH at... !A 100.0 mL aliquot of 0.200 M aqueous calcium hydroxide is mixed with ! 100.0 mL of 0.200 M aqueou... A 25.0 mL aliquot of a well-shaken and filtered sample of river is pipetted into an evaporating dish... A 10.00 mL aliquot of 0.100 M NaOH is added to 15.00 mL of 0.100M HCl in a coffee cup calorimeter. T... A 25.00 mL aliquot of HCl of unknown concentration is titrated with 25.62 mL of 0.1011 M NaOH. What... A 25.0 mL aliquot of vinegar was diluted to 250 mL in a volumetric flask . Titration of 50 mL aliqu... A 20.0mL aliquot of 0.100 M HCl is titrated with 0.100M NaOH solution. What is the pH of the resulti...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use