Asked by Sara
                The pH or acidity of liquid is measured in pH, where pH is given by the equation pH=- log C, with C being the concentration of [H+] in multiples of M=1mol/L. Suppose you are given a solution of hydrochloric acid with a pH of 1.7 and asked to increase the pH solution by 1.4. Determine by how much you must dilute the solution if the ratio of the concentration of two acids is c2/c1 . Does  your answer differ if you start with pH of 2.2
            
            
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    If pH(1) = 1.7 => [H+]=10^-1.7 = 0.020M
If pH(2) = 1.7 + 1.4 = 3.1 => [H+]=10^-3.1 = 0.0008
pH(1)/pH(2) = 0.020/0.00080 = 25X dilution
If pH(3) = 2.2 => [H+]=10^-2.2 = 0.0063M
If pH(4)= 2.2 + 1.4 = 3.6 => [H+]= 0.00025
pH(3)/pH(4)= 0.0063/0.00025 = 25X dilution
No
    
If pH(2) = 1.7 + 1.4 = 3.1 => [H+]=10^-3.1 = 0.0008
pH(1)/pH(2) = 0.020/0.00080 = 25X dilution
If pH(3) = 2.2 => [H+]=10^-2.2 = 0.0063M
If pH(4)= 2.2 + 1.4 = 3.6 => [H+]= 0.00025
pH(3)/pH(4)= 0.0063/0.00025 = 25X dilution
No
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