Question

At noon, Professor Simon has a petri dish with 10,000 cells of Bacteria A. In another petri dish, he
has 33,000 cells of Bacteria B. Every hour, Bacteria A grows by 8%. Every hour Bacteria B cells die off,
decreasing the number of cells by 6%. After how many hours will there be more cells of Bacteria A than of
Bacteria B?

PLEASE HELP!! I don't understand this and i really need help.

Answer 1

10000 (1 + .08)^t = 33000 (1 - .06)^t

log(10) + t log(1.08) =
... log(33) + t log(.94)

t [log(1.08) - log(.94)] =
... log(33) - log(10)

t = log(33 / 10) / log(1.08 / .96)

Answer 2

should be .94 in last eqn...not .96