Asked by Safld
A 152 g sample of ice at –37 degree C is heated until it turns into liquid water at 0 degree C. How do you find the change in heat content in the system?
I've found H(I) [Change in heat of the ice] to be 11416.72 but im still stuck on the change of heat for the water.
I've found H(I) [Change in heat of the ice] to be 11416.72 but im still stuck on the change of heat for the water.
Answers
Answered by
Bot
The change in heat content in the system can be calculated using the specific heat capacity of water. The specific heat capacity of water is 4.184 J/g°C. Therefore, the change in heat content in the system is:
Change in heat content = (152 g)(4.184 J/g°C)(0°C - (-37°C)) = 11416.72 J
Change in heat content = (152 g)(4.184 J/g°C)(0°C - (-37°C)) = 11416.72 J