Asked by sarah
secx - sinxtanx
Answers
Answered by
Steve
1/cosx - sinx/cosx = (1-sinx)/cosx
I guess you could go further, recalling that sin and cos are complementary functions, and get
(1-sinx)/cosx
= (1-cos(90-x))/sin(90-x)
= tan((90-x)/2)
= tan(45 - x/2)
I guess you could go further, recalling that sin and cos are complementary functions, and get
(1-sinx)/cosx
= (1-cos(90-x))/sin(90-x)
= tan((90-x)/2)
= tan(45 - x/2)
Answered by
Steve
Oops -- my bad!
secx - sinx tanx
= 1/cosx - sin^2x/cosx
= (1-sin^2x)/cosx
= cos^2x/cosx
= cosx
secx - sinx tanx
= 1/cosx - sin^2x/cosx
= (1-sin^2x)/cosx
= cos^2x/cosx
= cosx
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