Asked by Brynlie

A doubly charged helium atom (mass = 6.68 x 10-27 kg) is accelerated through a potential difference of 3.00x 103 V. What will be the radius of curvature of the path of the atom if it is in a uniform 0.410 T magnetic field?

Answers

Answered by Brynlie
The secod part of the question is...

What is the period of revolution for the atom in the previous question?
Answered by bobpursley
Get the velocity after acceleration in the electric field, then, with that velocity..

centripetal force= magnetic force
and solve for r.
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