Question

a bag of fruit contains 3 apples, 2 oranges, 1 banana, and 4 pears. Gerald will randomly select 2 fruit at a time from the bag and not put them back. what is the probability that the first piece of fruit jared selects will be a banana and the second piece of fruit will be of fruit be a pear

CAN SOMEONE PLEASE GUIDE ME THROUGH THIS IK THE ANSWER BUT IDK THE STEPS TO TAKE I NEED HELP ASAP PLEASE! THANK YOU!

Answer 1

There are 10 fruits.

P(banana) = 1/10
since there is only one banana. After the 1st pick, there are only 9 fruits left.

Now it should be clear what P(pear) is.

P(both) = P(banana) * P(pear)

Answer 2

The answer is 2/45. :)