Asked by Happinessdelight
For the equation
3^x - 3^-x = 1 solve for x by writing your final answer in logarithmic form.
3^x - 3^-x = 1 solve for x by writing your final answer in logarithmic form.
Answers
Answered by
Steve
let u = 3^x. Then you have
u - 1/u - 1 = 0
u^2-u-1 = 0
solve for u, and then x = log<sub>3</sub>u
u - 1/u - 1 = 0
u^2-u-1 = 0
solve for u, and then x = log<sub>3</sub>u
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