Asked by Alice
Complete and Balance the following equation using the half-reaction method;
(MnO4^-) + (CH3OH) --> (Mn^2+) + (HCO2H
an explanation/step by step would be nice because i keep getting wrong answer from the H+ & H2O (they are both suppose to be 12 according to the answer key but i can't get it)
I got 4MnO4^- +5CH3OH + 22H^+ ---> 4Mn^2+ +5HCO2H +11H2O
I Do
(MnO4^-) + (CH3OH) --> (Mn^2+) + (HCO2H
an explanation/step by step would be nice because i keep getting wrong answer from the H+ & H2O (they are both suppose to be 12 according to the answer key but i can't get it)
I got 4MnO4^- +5CH3OH + 22H^+ ---> 4Mn^2+ +5HCO2H +11H2O
I Do
Answers
Answered by
DrBob222
Here are tutorials on each phase of the redox process you may need. If you had shown your work I could hav found your problem easily. As it is I have no idea what you're doing wrong. The equation you posted isn't balanced, though, so you know it can't be right.
http://www.chemteam.info/Redox/Redox.html
http://www.chemteam.info/Redox/Redox.html
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