Asked by anonymos
When you take your 1700-kg car out for a spin, you go around a corner of radius 55 m with a speed of 20 m/s. The coefficient of static friction between the car and the road is 0.88.Assuming your car doesn't skid, what is the force exerted on it by static friction?
Answers
Answered by
Damon
m Ac = m v^2/r
= 1700 * 400 / 55 Newtons
= 1700 * 400 / 55 Newtons
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