Asked by Flor
If the thermometer reads 22 c and this corresponds to 19.8mmhg of water pressure , what is the pressure of a pure gas collected over water if the total pressure is 760 mmhg?next calculate the pressure of the gas and lets assume its hydrogen gas in atm.
pressure of pure gas=760-19.8mmhg
=740.2mmhg. That would be my P2
P1*V1=P2*V2
v2=P1*V1/p2
V2=19.8mmhg*1atm/740.2mmhg
Would my answer be ==0.02674.
Any help will be appreciated.
pressure of pure gas=760-19.8mmhg
=740.2mmhg. That would be my P2
P1*V1=P2*V2
v2=P1*V1/p2
V2=19.8mmhg*1atm/740.2mmhg
Would my answer be ==0.02674.
Any help will be appreciated.
Answers
Answered by
DrBob222
Your first calculation of P = 740.2 mm pressure for the pure (dry) gas is correct. The last part involving P1V1 = P2V2 isn't and I don't think you can calculate a volume of the H2 gas because you list no volumes in the problem. The numbers you have substituted are pressure values.
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