Question
With the center of a meter stick place on a knife edge balance and a 2N weight hanging on its 100cm mark, where should a 5N weight be placed to keep the meter stick in static equilibrium.
Answers
summing moments about the knife edge:
5(50-x)=2(100-50)
where x is the position
50-x=2(10)
x=30cm mark
5(50-x)=2(100-50)
where x is the position
50-x=2(10)
x=30cm mark
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