Asked by Thomas
                Following the recent census, State A, with a population of 13.5 million, was allocated 23 representatives. State B, with a population of 12.4 million, was given 16 representatives. Assume one more representative is to be assigned to one of these states. 
How do I solve this?
Do I take 13.5/23+1 =.5626
12.4/16=.775
.775-.5626=.2124
.2124/.5626=.377
.377 would be the relative unfairness
Then would I take
13.5/23=.5869
12.4/17=.7294
.7294-.5869=.1425
.1425/.7294=.195
.195 would be the second part to the first half.
The added representative would go to State B.
 
I do not know if I solved this question correctly.
Thanks for the help!
            
            
        How do I solve this?
Do I take 13.5/23+1 =.5626
12.4/16=.775
.775-.5626=.2124
.2124/.5626=.377
.377 would be the relative unfairness
Then would I take
13.5/23=.5869
12.4/17=.7294
.7294-.5869=.1425
.1425/.7294=.195
.195 would be the second part to the first half.
The added representative would go to State B.
I do not know if I solved this question correctly.
Thanks for the help!
Answers
                    Answered by
            Henry
            
    State A: 23rep./13.5mil. = 1.70  reps/mil.
State B: 16reps/12.4mil = 1.29 reps/mil.
State B has the least number of reps per mil; therefore, the last rep should be assigned to state B.
    
State B: 16reps/12.4mil = 1.29 reps/mil.
State B has the least number of reps per mil; therefore, the last rep should be assigned to state B.
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