Asked by Brianna
Air trapped in a cylinder fitted with a piston occupies 162.2 mL at 1.08 atm pressure. What is the new volume when the piston is depressed, increasing the pressure by 25%?
Answers
Answered by
Steve
assuming a constant temperature,
PV = kT is constant.
So, with 5/4 the pressure, you get 4/5 the volume
PV = kT is constant.
So, with 5/4 the pressure, you get 4/5 the volume
Answered by
Brianna
i dont understand
Answered by
DrBob222
You can do also by using
P1V1 = P2V2
P1 = 1.08 atm and P2 = 1.08+0.25*1.08 = ?
V1 is given. Solve for V2
P1V1 = P2V2
P1 = 1.08 atm and P2 = 1.08+0.25*1.08 = ?
V1 is given. Solve for V2
Answered by
Brianna
is it 1.23?
Answered by
Anonymous
116.56 ml
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