Question
Find the area of quadrilateral whose verties are A(0,2), B(2,7), C(6,10), and D (9,-2).
Answers
bobpursley
There is an old method, called Pick's theorem: https://en.wikipedia.org/wiki/Pick%27s_theorem
So graph the points on graph paper, count the points, and use the formula.
So graph the points on graph paper, count the points, and use the formula.
Henry
(AB)^2 = (2-0)^2 + (7-2)^2 = 29,
AB = 5.39.
(BC)^2 = (6-2)^2 + (10-7)^2 = 25,
BC = 5.
(CD)^2 = (9-6)^2 + -2-6)^2 = 73,
CD = 8.54.
(AD)^2 = ((9-0)^2 + (-2-2)^2 =
AD =
P = AB + BC + CD + AD =
A^2 = (P*AB*BC*CD*AD)/16 =
A =
AB = 5.39.
(BC)^2 = (6-2)^2 + (10-7)^2 = 25,
BC = 5.
(CD)^2 = (9-6)^2 + -2-6)^2 = 73,
CD = 8.54.
(AD)^2 = ((9-0)^2 + (-2-2)^2 =
AD =
P = AB + BC + CD + AD =
A^2 = (P*AB*BC*CD*AD)/16 =
A =