Question

suppose that sample of beef broth initially contains 16 bacterial cells. after 4.0 h, there are 1.6 x 106 bacterial cells in the sample. calculate the growth rate of the bacterial population for the given time interval. (record your answer in scientific notation: x x 10n )
PR= V(present)- V(past) divided by V(past)x100


PR= (1.6x106)- 16
-------------
16
PR= 153.6
-----
16
PR= 9.5 x 100

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