Question
in 2016, you purchased a new car for $20,000. The value of the car depreciates at a rate of 18% per year. The value V of the car after t years is given by the function V(t)=20000(0.82)t. When will the car be worth three-quarters of its original value?
Answers
V = Vi (0.82)^t not times t
.75 = .82^t
log .75 = t log .82
t = log.75 / log.82 = 1.45 years
.75 = .82^t
log .75 = t log .82
t = log.75 / log.82 = 1.45 years
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