Asked by STUDENT
What is the limiting reactant is if 0.5gAl is reacted with 3.5gCuCl2?
2Al(s)+3CuCl2(aq) --> 3Cu(s)+2AlCl3(aq)
2Al(s)+3CuCl2(aq) --> 3Cu(s)+2AlCl3(aq)
Answers
Answered by
bobpursley
moles Al=.5/27=.0185
Moles CuCl2=3.5/134.5= 0.0260
the balanced equation requires 3/2 moles CopperIIChloride/Al
you have .0260/.0185=1.20 so you dont have a 1.5 ratio, you have too little CuCl2, and it is the limiting reactant
Moles CuCl2=3.5/134.5= 0.0260
the balanced equation requires 3/2 moles CopperIIChloride/Al
you have .0260/.0185=1.20 so you dont have a 1.5 ratio, you have too little CuCl2, and it is the limiting reactant
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