Asked by koushik
In an isosceles triangle angle in the top vertex is twice the sum of the base angle. Find the exterior angles of the triangle.
Answers
Answered by
Ravi
Let vertex is x
Basa angles are 2x
We know that
Sum of angles in triangle is 180
X+2x+2x=180
5x= 180
X=36
Base angle=2(36)
=72
Exterior angles = sum of interior angles
=72+72
=144
Basa angles are 2x
We know that
Sum of angles in triangle is 180
X+2x+2x=180
5x= 180
X=36
Base angle=2(36)
=72
Exterior angles = sum of interior angles
=72+72
=144
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