Asked by Alex

Please help! I'm trying to find the solubility of Ca(OH)2 in .001305 mol/L aqueous NaOH?

Saturated solution of Ca(OH)2 in 0.01305 mol/L NaOH.
[HCl] = 0.1213 M
Volume of HCl = 9.81 mL
Volume of Ca(OH)2/NaOH aliquot = 25ml

Find:
1. the TOTAL [OH-] in the saturated solution of Ca(OH)2 in NaOH
2. the [OH-] due to dissolved Ca(OH)2
3. determine the solubility of Ca(OH)2 in the NaOH solution
4. the Ksp for Ca(OH)2 for the saturated solution of Ca(OH)2 in NaOH

Answers

Answered by DrBob222
http://www.jiskha.com/display.cgi?id=1489957110
Answered by DrBobPleaseHelp
Im still unsure of how to find #3 and #4, is the solubility the same for CaOH2 to NaOH :/?
Answered by Alex
When they multiplied concentration of NaOH with the total volume wouldn't that give you moles? That part is confusing to me, I'm unsure what to do next.
Answered by DrBobPleaseHelp
I believe for #3 the solubility for CaOH2 in NaOH would just be the Ca ion. But im unsure as of how to calculate it.
And for 4,Ksp for Ca(OH)2 is (Ca^+2)(OH^-)^2; im unsure of this too.
I think we have to wait for drbob to check this out for us.
Answered by Alex
Thanks, and for the #1 how do we get the [oh-] of Naoh to add to the total?
Answered by DrBob222
I'll try to take care of both questions but it may be confusing to try t answer both with one post.
For #3, yes, solubility Ca(OH)2 is (Ca^2+). You have total OH and you have OH from the NaOH. The difference is the OH from the Ca(OH)2 itself. 1/2 the OH from Ca(OH)2 gives the Ca^+ and that will be the solubility CaCO3 in mols/L. Convert that to grams if you wish but you will need it in M for #4. Where did the 1/2 come from? That's Ca(OH)2 ==> Ca^2+ + 2OH^- so (Ca^2+) is 1/2 (OH^-).
For #4, Just plug in the numbers.
Ksp = (Ca^2+)(OH^-)^2
You know Ca^2+ and you know OH^-, solve for Ksp. :-).

For Alex, yes M x L = mols. I almost never change out of mols when I work these things until I get to the final answer, then convert to the units the problem wants. For #1, M NaOH x L NaOH on the initial sample gives you TOTAL MOLS OH.
Answered by DrBobPleaseHelp
So basically take the [OH-] of caoh2, and divide it by 2 and we get [ca2+]?
Answered by DrBob222
Yes. Isn't that what the equation says?
Ca(OH)2 ==> Ca^2+ + 2OH^-
So if you know the OH from Ca(OH)2 then 1/2 that is Ca^2+. By the way you should write Ca(OH)2 right; the way you write it is not right and I know what it is only because I've been working with the problem.
Answered by Alex
Thank you guys sooooooo much! You are really helpful!
Answered by DrBobPleaseHelp
Thanks a lot sir. And yes i will make sure to write it correctly next time
Answered by Alex
PLEASE HELP! Consider the following galvanic cell: Ag(s) | Ag+(aq) || Cu2+(aq) | Cu(s)?

Match the components with their function in the cell.


1. |

2. ||

3. Ag(s) | Ag+(aq)

4. Cu2+(aq) | Cu(s)


A. Cathode Half Reaction

B. Phase boundary

C. Salt Bridge

D. Anode Half Reaction
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