-28=-.52molesglycol/kg solution
kg solution=massglycol+masswater
-28=-0.52(massglycol/molmassglycol)/(massglycol/1000 + 20kg)
where massglycol is in grams.
What volume of ethylene glycol (C2H6O2), a nonelectrolyte, must be added to 20.0 L of water to produce an antifreeze solution with a freezing point of -28.0°C? (The density of ethylene glycol is 1.11 g/cm3, and the density of water is 1.00 g/cm3.)
.....L
What is the boiling point of this solution?
......°C
1 answer