Asked by ranji public

An ordinary dice is rolled what are the odds against and in favour of the event "multiple of Three"?
Answered by bobpursley
multiple of three:3 or 6

pr (3or6)=2/6=1/3
pr(not 3or6)=1-1/3=2/3
Answered by Reiny
so the odds against multiple of three = (2/3) : (1/3)
= 2 : 1

the odds in favour of multiples of three = 1 : 2
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